A 20% increase followed by a 20% decrease does not restore the original value, because the second percentage is calculated from a different base.
1 · Why successive changes are multiplicative
Final=Initial×(1+r1)(1+r2)
2 · Choose the correct multiplier
Increase by p%:1+100pDecrease by p%:1−100p
3 · Worked example: unequal percentage changes
A company has 200 customers. Its customer count increases by 20% in the first month, then decreases by 20% in the second month. How many customers remain after the second month?
200(1+0.20)(1−0.20)=200(1.2)(0.8)=192
4 · Why equal rise and fall do not cancel
(1+r)(1−r)=1−r2Net loss=r2
5 · Reverse percentages: recover the original
0.80x=96⟹x=0.8096=120
6 · Changes across multiple stages
Vn=V0∏k=1n(1+rk)
7 · GMAT strategy: test with a convenient base
100+10%110+20%132⇒+32%
First, convert each percentage change into a multiplier. Then multiply the factors and compare the result with 1.00.
Think Like a GMAT Test-Taker
Identify the base quantity, then translate each percentage into a multiplier before computing.
The faster method
For successive +a% and +b% changes, the overall increase is a + b + ab/100 percent. For +p% then -p%, the overall loss is p²/100 percent.
Decision rule
When the original value is missing, divide the final value by the product of the multipliers; never reverse a discount by simply adding the percentage.
Common GMAT Traps
Adding consecutive percentage changes instead of multiplying factors.
Assuming +20% followed by -20% gives zero net change.
Applying a discount to the original base after an earlier increase.
Confusing a percentage-point change with a percentage change.